True or False:
5832/17496 + 2943/17658 = 6729/13458
Answer:
True............1/3 + 1/6 = 1/2
Also:
4392/175618 = 1/4
2769/1345 = 1/5
2394/16758 = 1/7
3187/25496 = 1/8
6381/57429 = 1/9
Wednesday, 27 January 2010
DAY 207
A man and his wife were expecting a baby, and the man wanted to give "the boy" 2/3 of his estate, and leave 1/3 to his wife. But in case "the boy" turned out to be "the girl," then 2/3 of his estate would go to his wife, and 1/3 to his daughter. As it turned out, they had twins---one boy and one girl. In keeping with his original plans, how should Dad settle his estate between his wife and two children?
HINT:
He wanted to give the mother twice as much as the daughter, and the son twice as much as the mother.
Answer:
1/7 to the daughter, 2/7 to his wife, and 4/7 to his son.
`
HINT:
He wanted to give the mother twice as much as the daughter, and the son twice as much as the mother.
Answer:
1/7 to the daughter, 2/7 to his wife, and 4/7 to his son.
`
Tuesday, 26 January 2010
DAY 206
A cyclist rode a mile in three minutes with the wind, and returned in four minutes against the wind. Assuming that he pedals at a constant rate, how long would it take him to cycle one mile on a windless day?
A cyclist rode a mile in three minutes with the wind, and returned in four minutes against the wind. Assuming that he pedals at a constant rate, how long would it take him to cycle one mile on a windless day?
Answer:
3 3/7 minutes..........If he can cycle 1 mile in three minutes with the wind (1/3 mile per minute), then he could cycle 1 1/3 (4/3) miles in four minutes with the wind. He returns against the wind in the same four minutes, so he can cycle 2 1/3 miles in eight minutes. The effect of the wind can now be ignored. So, on a windless day, he can cycle 7/3 miles in 8 minutes, or 8 divided by 7/3, one mile in 3 3/7 minutes.
3 3/7 minutes..........If he can cycle 1 mile in three minutes with the wind (1/3 mile per minute), then he could cycle 1 1/3 (4/3) miles in four minutes with the wind. He returns against the wind in the same four minutes, so he can cycle 2 1/3 miles in eight minutes. The effect of the wind can now be ignored. So, on a windless day, he can cycle 7/3 miles in 8 minutes, or 8 divided by 7/3, one mile in 3 3/7 minutes.
Tuesday, 19 January 2010
DAY 204
WHICH WITCH
Credit: GAMES Magazine - January, 1989
WHICH WITCH
Credit: GAMES Magazine - January, 1989
Karen Nimmons
If six witches can wind sixty watches in sixteen weeks, how many watches would sixty witches wind in six weeks?
Answer:
225............One witch can wind 10 watches in sixteen weeks. So one witch can wind 10/16 or 5/8 watches in one week. One witch could wind 6 x 5/8 or 30/8 watches in six weeks. Sixty witches could wind 60 x 30/8 or 225 watches in six weeks.
If six witches can wind sixty watches in sixteen weeks, how many watches would sixty witches wind in six weeks?
Answer:
225............One witch can wind 10 watches in sixteen weeks. So one witch can wind 10/16 or 5/8 watches in one week. One witch could wind 6 x 5/8 or 30/8 watches in six weeks. Sixty witches could wind 60 x 30/8 or 225 watches in six weeks.
Friday, 8 January 2010
DAY 203
COUNTING TEASE
Credit: GAMES Magazine - September, 2001
COUNTING TEASE
Credit: GAMES Magazine - September, 2001
D.A. Lavallee
Using the above title as a clue, what number logically comes next in the following sequence?
2, 3, 10, 12, 13, ___
Answer:
20..........The sequence is the set of positive integers that start in English with the letter T, written in ascending order. [Counting Tease (T's)]
Using the above title as a clue, what number logically comes next in the following sequence?
2, 3, 10, 12, 13, ___
Answer:
20..........The sequence is the set of positive integers that start in English with the letter T, written in ascending order. [Counting Tease (T's)]
Thursday, 7 January 2010
DAY 202
IT ALL ADDS UP
Credit: GAMES Magazine
July, 1985
IT ALL ADDS UP
Credit: GAMES Magazine
July, 1985
Michael W. Ecker
You and an opponent alternate picking numbers from 1 to 6, and a running total is kept. If the object of the game is to make the score total exactly 50, and you go first, what number should you pick to insure a win for yourself?
Answer:
Fifty is 1 more than a multiple of 7, so pick 1 as your number. Then, no matter what your opponent chooses, you say 7 minus that number. On your eighth turn, you will cause the score to hit 50 exactly.
You and an opponent alternate picking numbers from 1 to 6, and a running total is kept. If the object of the game is to make the score total exactly 50, and you go first, what number should you pick to insure a win for yourself?
Answer:
Fifty is 1 more than a multiple of 7, so pick 1 as your number. Then, no matter what your opponent chooses, you say 7 minus that number. On your eighth turn, you will cause the score to hit 50 exactly.
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