DAY 232
LEFTOVERS AGAIN?
Credit: GAMES Magazine
June, 1984
Michael W. Ecker
What is the smallest whole number that, when divided by 2 leaves a remainder of 1; when divided by 3, leaves a remainder of 2; and so on, and when divided by 10 leaves a remainder of 9?
Answer:
2,519...............Since the remainder is always 1 less than the divisor, it follows that the answer must be 1 less than a multiple of all the divisors 2 through 10. The smallest such number must be the Least Common Multiple of 2, 3, 4, ...........9, 10 minus 1. The LCM is 2,520, so the answer is 2, 519.
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment